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5y^2+24y-176=0
a = 5; b = 24; c = -176;
Δ = b2-4ac
Δ = 242-4·5·(-176)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4096}=64$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-64}{2*5}=\frac{-88}{10} =-8+4/5 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+64}{2*5}=\frac{40}{10} =4 $
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